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+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:d903acbbd579075c20da58df0664f6b615313ecea1f356fbfe69d66ce9759ff7"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 5 : Water and Wastewater Volumes"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.1 Page No : 5-6"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\t\n",
+      "#initialisation of variables\n",
+      "t1 = 5.25\t#yr\n",
+      "t2 = 10.00\t#yr\n",
+      "yi = 171000\t#in\n",
+      "ye = 111000\t#in\n",
+      "yt = 5.23300\t#in\n",
+      "yl = 5.04532\t#in\n",
+      "yn = 31500\t#in\n",
+      "ym = 0.09853\t#in\n",
+      "tm = 9.25\t#yr\n",
+      "tn = 10.00\t#yr\n",
+      "\t\n",
+      "#CALCULATIONS\n",
+      "T = t1/t2\t#yr\n",
+      "T1 = tm/tn\t#yr\n",
+      "Y = yi-ye\t#in\n",
+      "Yt = yt-yl\t#in\n",
+      "\t\n",
+      "#RESULTS\n",
+      "print 'the fifth intercensal year  = %.3f yr'%(T)\n",
+      "print 'the ninth postcensal year  = %.3f yr'%(T1)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "the fifth intercensal year  = 0.525 yr\n",
+        "the ninth postcensal year  = 0.925 yr\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.2 Page No : 5-8"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "from sympy import Symbol\n",
+      "import math\n",
+      "\n",
+      "#initialisation of variables\n",
+      "y0 = 30000\t#in\n",
+      "y1 = 172000\t#in\n",
+      "y2 = 292000\t#in\n",
+      "a = 172\t     #ft\n",
+      "p = 30.\t    #ft\n",
+      "y = 292\t    #ft\n",
+      "q = 322000\t#ft\n",
+      "g = 313\t    #ft\n",
+      "n = 0.05\t#ft\n",
+      "d = -2.442\t#ft\n",
+      "t = Symbol('t')\n",
+      "\n",
+      "#CALCULATIONS\n",
+      "L = (2*p*a*y2-(a)**2*q)/(p*y-(a)**2)\t#moreover\n",
+      "m = (g-p)/p\t#ft\n",
+      "N = n*d\t#in\n",
+      "Y = g/(1+9.43*math.exp(N)*t)\t#in\n",
+      "\t\n",
+      "#RESULTS\n",
+      "print 'the saturation populations = %.2f moreover'%(round(L,-3))\n",
+      "print 'the coefficients = %.3f in'%(N)\n",
+      "print 'the equation of a logistic curve = ',(Y)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "the saturation populations = 313000.00 moreover\n",
+        "the coefficients = -0.122 in\n",
+        "the equation of a logistic curve =  313/(8.34611446180163*t + 1)\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.4 Page No : 5-19"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\n",
+      "#initialisation of variables\n",
+      "p = 100000\t#in\n",
+      "d = 150.\t#in\n",
+      "h = 1000000.\t#in\n",
+      "a1 = 2.0\t#draft\n",
+      "a2 = 3.0\t#draft\n",
+      "a3 = 1.6\t#draft\n",
+      "m = 1.5\t    #in\n",
+      "q = 2.5\t    #in\n",
+      "v = 1020.\t#in\n",
+      "w = 100. \t#in\n",
+      "t = 0.01\t#in\n",
+      "v1 = 13.2\t#mgd\n",
+      "\t\n",
+      "#CALCULATIONS\n",
+      "A = d*p/h\t#mgd\n",
+      "M = m*A\t#mgd\n",
+      "M1 = q*A\t#mgd\n",
+      "V = v*math.sqrt(w)*(1-t*math.sqrt(w))\t#gpm\n",
+      "D = M+v1\t#mgd\n",
+      "L = a1*A\t#mgd\n",
+      "L1 = (4./3)*M\t#max\n",
+      "H = a2*A\t#mgd\n",
+      "H1 = (4./3)*M1\t#max\n",
+      "F = a3*A\t#mgd\n",
+      "F1 = (1.6)*15\t#max\n",
+      "\t\n",
+      "#RESULTS\n",
+      "print 'the resulting capacities of the four system  = %.f max'%(F1)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "the resulting capacities of the four system  = 24 max\n"
+       ]
+      }
+     ],
+     "prompt_number": 8
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.6 Page No : 5-22"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\t\n",
+      "#initialisation of variables\n",
+      "r = 48\t#in\n",
+      "A = 450\t#gpd/acre\n",
+      "B = 8000.\t#gpd/mile\n",
+      "S = round(5280./350)\t#manholes/mile\n",
+      "\n",
+      "#CALCULATIONS\n",
+      "C = (B-S*100)/12\t#gpd/mile\n",
+      "\n",
+      "#RESULTS\n",
+      "print 'the ground a quarter of it eventually  = %.2f gpd/mile'%(C)\n",
+      "\n",
+      "# note : answer in book is wrong. please check."
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "the ground a quarter of it eventually  = 541.67 gpd/mile\n"
+       ]
+      }
+     ],
+     "prompt_number": 2
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.7 Page No : 5-23"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\t\n",
+      "#initialisation of variables\n",
+      "p1 = 20.\t#ft\n",
+      "p2 = 30.\t#ft\n",
+      "w = 5.  \t#person\n",
+      "s = 17800.\t#in\n",
+      "h = 1200.\t#in\n",
+      "q = 100. \t#in\n",
+      "i = 1.\t#in\n",
+      "\t\n",
+      "#CALCULATIONS\n",
+      "S = p1*p2*i*s/(h*w)\t#gpcd\n",
+      "P = (q*w*10/S)\t#percent\n",
+      "\n",
+      "\n",
+      "#RESULTS\n",
+      "print 'the degree of separation of stormwater = %.0f percent'%(P)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "the degree of separation of stormwater = 3 percent\n"
+       ]
+      }
+     ],
+     "prompt_number": 15
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.8 Page No : 5-24"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\t\n",
+      "#initialisation of variables\n",
+      "s = 105\t#gpcd\n",
+      "m = 315\t#gpcd\n",
+      "m1 = 35\t#gpcd\n",
+      "Q1 = 360\t#gpcd\n",
+      "Q2 = 30\t#gpcd\n",
+      "p1 = 20\t#pecent\n",
+      "p2 = 15\t#persons/acer\n",
+      "D = 21\t#persons/acre\n",
+      "I = 2000\t#gpd/acre\n",
+      "\t\n",
+      "#CALCULATIONS\n",
+      "A = D*(s+Q2)+I\t#gpd/acre\n",
+      "R = D*(m+Q2)+I\t#gpd/acre\n",
+      "L = D*(m1+Q2)+I\t#gpd/acre\n",
+      "\t\n",
+      "#RESULTS\n",
+      "print 'the average peak and low rates of flow  = %.0f gpd/acre'%(round(L,-1))\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "the average peak and low rates of flow  = 3370 gpd/acre\n"
+       ]
+      }
+     ],
+     "prompt_number": 16
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
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