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authorTrupti Kini2017-03-17 23:30:25 +0600
committerTrupti Kini2017-03-17 23:30:25 +0600
commit2a5f1f9f2af82c46fbdba902c9dfdaba56c136b0 (patch)
tree7ce76ec82cb74706a939781d9bf0c7c9afab53e5 /Introduction_to_Heat_Transfer_by_S._K._Som/Chapter10.ipynb
parentd93e64cd264d30ae87de69ab9ab7f377d6047361 (diff)
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Added(A)/Deleted(D) following books
M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter1.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter10.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter11.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter2.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter3.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter4.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter5.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter6.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter7.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter8.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter9.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/chapter12.ipynb
Diffstat (limited to 'Introduction_to_Heat_Transfer_by_S._K._Som/Chapter10.ipynb')
-rw-r--r--Introduction_to_Heat_Transfer_by_S._K._Som/Chapter10.ipynb138
1 files changed, 7 insertions, 131 deletions
diff --git a/Introduction_to_Heat_Transfer_by_S._K._Som/Chapter10.ipynb b/Introduction_to_Heat_Transfer_by_S._K._Som/Chapter10.ipynb
index 95f29d79..9eacc4ed 100644
--- a/Introduction_to_Heat_Transfer_by_S._K._Som/Chapter10.ipynb
+++ b/Introduction_to_Heat_Transfer_by_S._K._Som/Chapter10.ipynb
@@ -44,10 +44,6 @@
}
],
"source": [
- " \n",
- " \n",
- " \n",
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 10, Example 1\"\n",
@@ -94,29 +90,7 @@
"print\"LMTD=\",LMTD\n",
"print\"Area(A)=Q/(U*LMTD) in m**2\"\n",
"A=Q/(U*LMTD)\n",
- "print\"A=\",A\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"A=\",A"
]
},
{
@@ -150,10 +124,6 @@
}
],
"source": [
- " \n",
- " \n",
- " \n",
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 10, Example 2\"\n",
@@ -193,7 +163,7 @@
"#Area(A)=Q/(U*LMTD) in m**2\n",
"print\"Area(A)=Q/(U*LMTD) in m**2\"\n",
"A=Q/(U*LMTD)\n",
- "print\"A=\",A\n"
+ "print\"A=\",A"
]
},
{
@@ -233,10 +203,6 @@
}
],
"source": [
- " \n",
- " \n",
- " \n",
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 10, Example 3\"\n",
@@ -284,13 +250,7 @@
"#overall heat transfer coefficient(U)=Q/(A*F*LMTD)\n",
"print\"overall heat transfer coefficient(U)=Q/(A*F*LMTD)in W/(m**2*K)\"\n",
"U=Q/(A*F*LMTD)\n",
- "print\"U=\",U\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"U=\",U"
]
},
{
@@ -342,10 +302,6 @@
}
],
"source": [
- " \n",
- " \n",
- " \n",
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 10, Example 5\"\n",
@@ -424,33 +380,7 @@
"print\"To provide this surface area ,The length(L) of the tube required is given by L=A/(pi*D) in m\"\n",
"L=A/(math.pi*D)\n",
"print\"Hence same result is obtained for both methods\"\n",
- "print\"L=\",L\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"L=\",L"
]
},
{
@@ -482,10 +412,6 @@
}
],
"source": [
- " \n",
- " \n",
- " \n",
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 10, Example 6\"\n",
@@ -520,13 +446,7 @@
"#Hence The total heat transfer rate (Q)=eff*Cmin*(Thi-Tci)in kW.\n",
"print\"The total heat transfer rate (Q)=eff*Cmin*(Thi-Tci) in kW\" \n",
"Q=eff*Cmin*(Thi-Tci)\n",
- "print\"Q=\",Q\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"Q=\",Q"
]
},
{
@@ -560,10 +480,6 @@
}
],
"source": [
- " \n",
- " \n",
- " \n",
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 10, Example 7\"\n",
@@ -603,22 +519,7 @@
"#The exit temprature(Tho) of air is given by Thi-(Q/(mdota*cpa))\n",
"print\"The exit temprature of air in °C \"\n",
"Tho=Thi-(Q/(mdota*1000*cpa))#NOTE:-The answer slightly varies from the answer in book(i.e Tho=26°C) because the value of Q taken in book is approximated to 1*10**6W.\n",
- "print\"Tho=\",Tho\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"Tho=\",Tho"
]
},
{
@@ -656,10 +557,6 @@
}
],
"source": [
- " \n",
- " \n",
- " \n",
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 10, Example 8\"\n",
@@ -702,28 +599,7 @@
"Tho=Tci;\n",
"print\"Effectiveness of heat exchanger is \"\n",
"eff=(mdoth*ch*(Thi-Tho))/(mdoth*ch*(Thi-Tci))\n",
- "print\"eff=\",eff\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"eff=\",eff"
]
}
],