// Copyright (C) 2018 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_V2-en.txt // Author:[insert name] // Organization: FOSSEE, IIT Bombay // Email: toolbox@scilab.in function [r, p, f, m] = residuez(B, A, tol) // RESIDUEZ - return residues, poles, and FIR part of B(z)/A(z) // // Let nb = length(b), na = length(a), and N=na-1 = no. of poles. // If nb= na, the FIR part f will not be empty. // Let M = nb-na+1 = order of f = length(f)-1). Then the returned filter is // // H(z) = f(1) + f(2)/z + f(3)/z^2 + ... + f(M+1)/z^M + R(z) // // where R(z) is the parallel one-pole filter bank defined above. // Note, in particular, that the impulse-response of the one-pole // filter bank is in parallel with that of the the FIR part. This can // be wasteful when matching the initial impulse response is important, // since F(z) can already match the first N terms of the impulse // response. To obtain a decomposition in which the impulse response of // the IIR part R(z) starts after that of the FIR part F(z), use RESIDUED. // //NOTE that the polynomials 'b' and 'a' should have real coefficients(because of the function 'filter' used in polyval) //Testcase //B=[1 1 1]; A=[1 -2 1]; //[r,p,f,m] = residuez(B,A) //OUTPUT: //r=[0;3] //p=[1;1] //f=1 //e=[1;2] [nargout,nargin]=argn(); if nargin==3 warning("tolerance ignored"); end NUM = B(:)'; DEN = A(:)'; // Matlab's residue does not return m (since it is implied by p): [r,p,f,m]=residue(conj(mtlb_fliplr(NUM)),conj(mtlb_fliplr(DEN))); p = 1 ./ p; r = r .* ((-p) .^m); if f f = conj(mtlb_fliplr(f)); end endfunction