<?xml version="1.0" encoding="UTF-8"?> <!-- * * This help file was generated from ifft1.sci using help_from_sci(). * --> <refentry version="5.0-subset Scilab" xml:id="ifft1" xml:lang="en" xmlns="http://docbook.org/ns/docbook" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:svg="http://www.w3.org/2000/svg" xmlns:ns3="http://www.w3.org/1999/xhtml" xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:scilab="http://www.scilab.org" xmlns:db="http://docbook.org/ns/docbook"> <refnamediv> <refname>ifft1</refname> <refpurpose>Calculates the inverse discrete Fourier transform of a matrix using Fast Fourier Transform algorithm.</refpurpose> </refnamediv> <refsynopsisdiv> <title>Calling Sequence</title> <synopsis> ifft (x, n, dim) ifft (x, n) ifft (x) </synopsis> </refsynopsisdiv> <refsection> <title>Parameters</title> <variablelist> <varlistentry><term>x:</term> <listitem><para> input matrix</para></listitem></varlistentry> <varlistentry><term>n:</term> <listitem><para> Specifies the number of elements of x to be used</para></listitem></varlistentry> <varlistentry><term>dim:</term> <listitem><para> Specifies the dimention of the matrix along which the inverse FFT is performed</para></listitem></varlistentry> </variablelist> </refsection> <refsection> <title>Description</title> <para> This is an Octave function. </para> </refsection> <refsection> <title>Description</title> <para> This is an Octave function. The inverse FFT is calculated along the first non-singleton dimension of the array. Thus, inverse FFT is computed for each column of x. </para> <para> n is an integer specifying the number of elements of x to use. If n is larger than dimention along. which the inverse FFT is calculated, then x is resized and padded with zeros. Similarly, if n is smaller, then x is truncated. </para> <para> dim is an integer specifying the dimension of the matrix along which the inverse FFT is performed. </para> </refsection> <refsection> <title>Examples</title> <programlisting role="example"><![CDATA[ x = [1 2 3; 4 5 6; 7 8 9] n = 3 dim = 2 ifft1 (x, n, dim) ans = 2.00000 + 0.00000i -0.50000 - 0.28868i -0.50000 + 0.28868i 5.00000 + 0.00000i -0.50000 - 0.28868i -0.50000 + 0.28868i 8.00000 + 0.00000i -0.50000 - 0.28868i -0.50000 + 0.28868i ]]></programlisting> </refsection> </refentry>